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One-Sided Limits (AP Exam Favorite)

Calculus I

Here's where the AP exam gets clever. It doesn't just test the regular limit — it tests whether the function approaches the same value from the LEFT and from the RIGHT

Notes & explanation

Builds directly on the limit notation from the previous video by adding the small −- and ++ superscripts.

Reading the notation

lim⁡x→2−f(x)vslim⁡x→2+f(x)\lim_{x \to 2^-} f(x) \qquad \text{vs} \qquad \lim_{x \to 2^+} f(x)

  • The minus means approaching from the left — from xx values less than 22.
  • The plus means approaching from the right — from xx values greater than 22.

The video notes both phrasings mean the same thing; pick whichever you find easier to remember and stick with it.

When does the limit exist?

lim⁡x→af(x)=L  ⟺  lim⁡x→a−f(x)=lim⁡x→a+f(x)=L\lim_{x \to a} f(x) = L \iff \lim_{x \to a^-} f(x) = \lim_{x \to a^+} f(x) = L

("iff" is just mathematician shorthand for if and only if.) So you must check both sides before you can claim the two-sided limit exists.

Worked example

Two graphs are read off the board, f(x)f(x) and g(x)g(x), each asking for the limit as x→2x \to 2.

For f(x)f(x): approaching 22 from the left, the yy-values close in on 44; approaching from the right, they also close in on 44. The one-sided limits agree, so

lim⁡x→2f(x)=4\lim_{x \to 2} f(x) = 4

For g(x)g(x): approaching from the left, the yy-values climb towards 22 (the graph shows an open circle there — gg is not defined at that point, but the limit only cares about the journey). Approaching from the right, the graph jumps to a visibly higher branch and the yy-values head towards a different, larger value. Since

lim⁡x→2−g(x)≠lim⁡x→2+g(x)\lim_{x \to 2^-} g(x) \neq \lim_{x \to 2^+} g(x)

the two-sided limit does not exist, written DNE on the board.