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Understanding Continuity (Calculus)

Calculus I

Three continuity conditions and a worked example

Notes & explanation

Note for review: this video's audio and visuals are identical to "Continuity (When the Limit Equals the Function Value)" (Tqy_pf-CJwU) — the same lesson appears to have been uploaded twice under different titles. Only one of the two should be published.

The informal definition

A function is continuous if you can draw its graph without lifting your pencil — no holes, no jumps, no breaks.

The formal definition

Formally, ff is continuous at x=ax = a if and only if all three conditions hold:

  1. f(a)f(a) is defined
  2. lim⁡x→af(x)\displaystyle\lim_{x \to a} f(x) exists
  3. lim⁡x→af(x)=f(a)\displaystyle\lim_{x \to a} f(x) = f(a)

The third condition is the point of the lesson: the limit must equal the actual function value.

Worked example

Determine whether f(x)=x2+1f(x) = x^2 + 1 is continuous at x=2x = 2.

Condition 1: f(2)=22+1=5f(2) = 2^2 + 1 = 5, so it is defined.

Condition 2: polynomials are continuous everywhere, so direct substitution is valid and lim⁡x→2f(x)=22+1=5\displaystyle\lim_{x \to 2} f(x) = 2^2 + 1 = 5.

Condition 3: both equal 55, so they match.

All three hold, therefore ff is continuous at x=2x = 2.

Exam note

On free-response questions, write the notation out fully and show each condition — marks are easily lost on presentation.