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Jump Discontinuities (When the Limit Does Not Exist)

Calculus I

A jump discontinuity occurs when the function approaches two different values from the left and right side of a point. Picture a staircase instead of a ramp, a ramp is smooth and continuous, but a staircase has a sudden vertical jump at each step. That jump is exactly what this discontinuity looks like on a graph

Notes & explanation

What a jump discontinuity is

A jump discontinuity occurs when the function approaches two different values from the left and from the right of a point.

Formal notation

lim⁡x→a−f(x)≠lim⁡x→a+f(x)\lim_{x \to a^-} f(x) \neq \lim_{x \to a^+} f(x)

The video sketches this: a curve coming in towards x=2x = 2 from the left and settling at one height, and a separate branch leaving x=2x = 2 from the right at a different height — a visible gap between the two.

Worked example

f(x)={x+1x<2x2x≥2f(x) = \begin{cases} x + 1 & x < 2 \\ x^2 & x \geq 2 \end{cases}

This is a piecewise function, so each side uses a different rule.

The method used throughout: always try direct substitution first — if the piece is a polynomial or otherwise continuous, you get a real number and can stop there.

Left-hand limit. Approaching from xx values less than 22, the function is x+1x + 1:

lim⁡x→2−f(x)=lim⁡x→2−(x+1)=2+1=3\lim_{x \to 2^-} f(x) = \lim_{x \to 2^-} (x + 1) = 2 + 1 = 3

Right-hand limit. Approaching from xx values greater than 22, the function is x2x^2:

lim⁡x→2+f(x)=lim⁡x→2+x2=22=4\lim_{x \to 2^+} f(x) = \lim_{x \to 2^+} x^2 = 2^2 = 4

Conclusion. The one-sided limits disagree:

lim⁡x→2−f(x)≠lim⁡x→2+f(x)  ⟹  lim⁡x→2f(x) DNE\lim_{x \to 2^-} f(x) \neq \lim_{x \to 2^+} f(x) \implies \lim_{x \to 2} f(x) \ \text{DNE}

and because they disagree by a finite gap, this is a jump discontinuity.